Chemistry Equilibrium Test
Multiple Choice Questions (MCQs)
- In a homogeneous equilibrium, all reactants and products are:
- (A) In different phases
- (B) In the same phase
- (C) Either in liquid or solid phase
- (D) Either in solid or gaseous phase
- Which of the following statements is correct regarding a heterogeneous equilibrium?
- (A) The concentration of solids and liquids is included in the equilibrium expression
- (B) Only gases are considered when writing the equilibrium constant expression
- (C) Solids are ignored, but liquids are included in the equilibrium constant expression
- (D) Solids and liquids are both ignored when writing the equilibrium constant expression
- The equilibrium constant Kc for a reaction is expressed in terms of:
- (A) Partial pressures of reactants and products
- (B) Concentrations of reactants and products
- (C) Number of moles of reactants and products
- (D) Temperature of the reaction
- For the reaction N2(g) + 3H2(g) ↔ 2NH3(g), the expression for Kp in terms of Kc is:
- (A) Kp = Kc(RT)2
- (B) Kp = Kc(RT)3
- (C) Kp = Kc(RT)-1
- (D) Kp = Kc(RT)-2
- In a reaction where Kp > Kc, we can conclude that:
- (A) There are more reactants than products at equilibrium
- (B) The reaction is at equilibrium under high pressure
- (C) The number of moles of gaseous products is greater than that of gaseous reactants
- (D) The number of moles of gaseous reactants is greater than that of gaseous products
Assertion-Reason Questions
For each of the following questions, choose:
- (A) If both assertion and reason are correct, and the reason is the correct explanation of the assertion
- (B) If both assertion and reason are correct, but the reason is not the correct explanation of the assertion
- (C) If the assertion is correct, but the reason is incorrect
- (D) If both the assertion and reason are incorrect
- Assertion: In the equilibrium expression for a reaction involving a solid, the concentration of the solid is not included.
Reason: Solids have a fixed concentration due to their constant density, which does not change during the reaction. - Assertion: For a reaction where the number of moles of gas changes, Kp and Kc will have different values.
Reason: Kp and Kc differ by a factor that depends on the number of moles of gaseous reactants and products and the temperature. - Assertion: In a heterogeneous equilibrium involving gases and solids, only the gaseous components are included in the equilibrium constant expression.
Reason: The concentration of solids remains constant and thus does not affect the equilibrium state. - Assertion: If Kp = Kc, then the number of moles of gaseous reactants is equal to that of gaseous products.
Reason: Kp and Kc are related through the equation Kp = Kc(RT)Δn, where Δn = 0 when moles of reactants equal moles of products. - Assertion: For the reaction CO(g) + H2O(g) ↔ CO2(g) + H2(g), the equilibrium constant is unaffected by changes in the concentration of solids present.
Reason: This reaction only involves gases, so the presence or absence of solids does not impact Kc or Kp.
One-Word Answer Questions
- In a chemical equilibrium expression, which state of matter is not included for any substance?
- If Δn for a reaction is zero, what is the relation between Kp and Kc?
- What do we call the equilibrium constant that is expressed in terms of the partial pressures of gases?
- In the equilibrium reaction CaCO3(s) ↔ CaO(s) + CO2(g), which component(s) would be included in the expression for Kp?
- For the reaction 2NO(g) + O2(g) ↔ 2NO2(g), if Kp = 1.5 × 103 at a certain temperature, what is the equilibrium constant for the reverse reaction?
Answers for Chemistry Equilibrium Test
Multiple Choice Questions (MCQs)
- (B)
- (D)
- (B)
- (A)
- (D)
Assertion-Reason Questions
- (A)
- (A)
- (A)
- (A)
- (B)
One-Word Answer Questions
- Solid
- Kp = Kc
- Kp
- CO2(g)
- 6.67 × 10-4
HW QUESTIONS
Equilibrium – 2 Marker Questions and Numericals
2-Mark Questions
- Define homogeneous and heterogeneous equilibrium with one example each.
- Explain why solids and liquids are not included in the expression for equilibrium constant, Kc.
- Differentiate between Kc and Kp with respect to chemical equilibrium.
- State the Law of Chemical Equilibrium and write the expression for the equilibrium constant for the reaction:
aA + bB ↔ cC + dD. - If the equilibrium constant Kc for a reaction is very large, what does it imply about the extent of the reaction? Explain.
Numerical Problems
- For the reaction
H2(g) + I2(g) ↔ 2HI(g),
the equilibrium concentrations at 700 K are: [H2] = 0.2 mol/L, [I2] = 0.1 mol/L, and [HI] = 1.2 mol/L. Calculate Kc for the reaction. - At a certain temperature, the equilibrium constant Kp for the reaction
N2O4(g) ↔ 2NO2(g)
is 0.113. If the partial pressure of N2O4 at equilibrium is 0.5 atm, calculate the partial pressure of NO2 at equilibrium. - The equilibrium constant Kp for the reaction
SO2(g) + (1/2)O2(g) ↔ SO3(g)
is 4.34 at 300 K. Calculate Kc for this reaction at the same temperature. (Given R = 0.0821 L atm K-1 mol-1). - For the reaction
CO(g) + 3H2(g) ↔ CH4(g) + H2O(g),
the equilibrium constant Kc is 0.18 at a certain temperature. If the initial concentration of CO is 0.2 mol/L and H2 is 0.3 mol/L, calculate the equilibrium concentrations of CH4 and H2O if they start at zero concentration. - A reaction has an equilibrium constant Kc = 1.6 × 103 at 500 K. If the initial concentration of the reactant is 0.5 mol/L, calculate the equilibrium concentration of the product if it starts from zero concentration. Assume the reaction is:
A ↔ B.