Haloalkanes L7


Section A: Multiple Choice Questions (1 mark each)

  1. Which of the following is a product of Wurtz reaction?
    a) Alkene
    b) Alkyne
    c) Alkane
    d) Alcohol
  2. Which reagent gives elimination as the major product with 2-bromopentane?
    a) Aqueous KOH
    b) Alcoholic KOH
    c) KCN
    d) AgNO3
  3. SN1 mechanism is favored by:
    a) Primary halides
    b) Secondary halides
    c) Tertiary halides
    d) All halides equally
  4. Which of the following reacts with haloarenes in Wurtz-Fittig reaction?
    a) Another aryl halide
    b) Sodium alkoxide
    c) Alkyl halide + Na
    d) Sodium nitrite
  5. The elimination reaction of 2-bromobutane in alcoholic KOH gives:
    a) Butan-2-ol
    b) But-1-ene and But-2-ene
    c) Butane
    d) 2-chlorobutane

Section B: Assertion and Reason (1 mark each)

  1. Assertion (A): Alcoholic KOH induces β-elimination in haloalkanes.
    Reason (R): The OH⁻ acts as a base and abstracts a proton.
  2. Assertion (A): SN2 reactions are faster in primary alkyl halides.
    Reason (R): Less steric hindrance allows easy backside attack.
  3. Assertion (A): Aryl halides do not easily undergo nucleophilic substitution.
    Reason (R): Resonance stabilization and partial double bond character in C–X bond.

Section C: One Word/One Line Answer (1 mark each)

  1. Name the reaction: Alkyl halide + Na + Alkyl halide → Alkane.
  2. What is the role of dry ether in Wurtz reaction?
  3. What type of product is obtained when haloalkane reacts with alcoholic KOH?

Section D: Short Answer Questions (2 marks each)

  1. Explain with an example the difference between SN1 and SN2 mechanisms.
  2. Write a balanced chemical equation for the Wurtz-Fittig reaction and name the product.

Section E: Short Answer Question (3 marks)

  1. Complete and write the products for the following reactions:
    (a) C2H5Br + alcoholic KOH → ?
    (b) Bromobenzene + CH3Br + Na (in dry ether) → ?
    (c) C2H5Br + KCN → ?

Section A: Multiple Choice Questions

  1. Answer: c) Alkane
  2. Answer: b) Alcoholic KOH
  3. Answer: c) Tertiary halides
  4. Answer: c) Alkyl halide + Na
  5. Answer: b) But-1-ene and But-2-ene

Section B: Assertion and Reason

  1. Answer: a) Both Assertion and Reason are true, and Reason is the correct explanation.
  2. Answer: a) Both Assertion and Reason are true, and Reason is the correct explanation.
  3. Answer: a) Both Assertion and Reason are true, and Reason is the correct explanation.

Section C: One Word/One Line Answers

  1. Answer: Wurtz reaction
  2. Answer: Solvent and reaction medium for the sodium metal
  3. Answer: Alkene (via β-elimination)

Section D: Short Answer Questions

  1. Answer:
    – **SN1** is a two-step mechanism, involves carbocation intermediate, e.g., (CH₃)₃CBr → (CH₃)₃COH
    – **SN2** is a single-step backside attack with inversion, e.g., CH₃CH₂Br + OH⁻ → CH₃CH₂OH
  2. Answer:
    C₆H₅Br + CH₃Br + 2Na → C₆H₅CH₃ + 2NaBr
    (This is the **Wurtz-Fittig reaction**; product is toluene)

Section E: Short Answer Question (3 Marks)

  1. Answer:
    • (a) C₂H₅Br + alcoholic KOH → CH₂=CH₂ + HBr + H₂O (Ethene formed via β-elimination)
    • (b) C₆H₅Br + CH₃Br + 2Na → C₆H₅CH₃ + 2NaBr (Toluene via Wurtz-Fittig reaction)
    • (c) C₂H₅Br + KCN → C₂H₅CN + KBr (Ethyl cyanide via nucleophilic substitution)